This is Australia's lowest score in the first innings against India in the history of Test cricket. Earlier in 1947, India had bowled out Australia for just 107 runs in the first innings. Not only this, this is Australia's third smallest total at home since 2000.
Australia's lowest score at home since 2000
85 vs South Africa Hobart 2016
98 vs England Melbourne 2010
104 vs India Perth 2024*
127 vs pakistan sydney 2010
136 vs New Zealand Hobart 2011
At the same time, this has become the third lowest score for India, after which India has been successful in gaining the lead. Earlier, Team India had managed to take a lead of 13 runs by scoring 147 runs against England at Lord's in 1936. At the top of this list is the 2002 Hamilton match against New Zealand when India scored 99 runs and took a lead of 5 runs.
Talking about this match, India took a significant lead of 46 runs by bowling out host Australia for 104 runs in the first innings. India's acting captain Jasprit Bumrah took five wickets and Harshit Rana took three wickets. India had scored 150 runs in its first innings.
Australia started yesterday's game ahead by 67 runs for seven wickets. Australia lost two wickets early and their score became 79 runs for nine wickets. Bumrah got Alex Carey caught by wicketkeeper Rishabh Pant. Carey scored 21 runs. This was Bumrah's fifth wicket. He took four wickets yesterday.
Harshit Rana took Australia's ninth wicket by getting Nathan Lyon caught by KL Rahul in the slips. But after this, Mitchell Starc and Josh Hazlewood made a partnership of 25 runs for the last wicket and took the host team beyond 100. Rana trapped Australia's innings at 104 runs by getting Starc caught by Pant. Starc scored a useful 26 runs in 112 balls, which was the highest score for his team. Hazlewood remained unbeaten on seven runs. For India, Bumrah took five wickets for 30 runs in 18 overs, while Mohammad Siraj took two wickets for 20 runs and Rana took three wickets for 48 runs.
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